142033121142041 has 2 divisors, whose sum is σ = 142033121142042. Its totient is φ = 142033121142040.

The previous prime is 142033121142023. The next prime is 142033121142053. The reversal of 142033121142041 is 140241121330241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119159820121225 + 22873301020816 = 10916035^2 + 4782604^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142033121142041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142033121141995 and 142033121142013.

It is not a weakly prime, because it can be changed into another prime (142033121142001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71016560571020 + 71016560571021.

It is an arithmetic number, because the mean of its divisors is an integer number (71016560571021).

Almost surely, 2^{142033121142041} is an apocalyptic number.

It is an amenable number.

142033121142041 is a deficient number, since it is larger than the sum of its proper divisors (1).

142033121142041 is an equidigital number, since it uses as much as digits as its factorization.

142033121142041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 142033121142041 its reverse (140241121330241), we get a palindrome (282274242472282).

The spelling of 142033121142041 in words is "one hundred forty-two trillion, thirty-three billion, one hundred twenty-one million, one hundred forty-two thousand, forty-one".