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142033213433 is a prime number
BaseRepresentation
bin1000010001000111010…
…1101101011111111001
3111120121112112211020102
42010101311231133321
54311341000312213
6145125452405145
713155500252156
oct2042165553771
9446545484212
10142033213433
1155266056521
122363a7767b5
1310516b97b77
146c3569122d
153a64495158
hex2111d6d7f9

142033213433 has 2 divisors, whose sum is σ = 142033213434. Its totient is φ = 142033213432.

The previous prime is 142033213423. The next prime is 142033213451. The reversal of 142033213433 is 334312330241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136787543104 + 5245670329 = 369848^2 + 72427^2 .

It is a cyclic number.

It is not a de Polignac number, because 142033213433 - 236 = 73313736697 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142033213396 and 142033213405.

It is not a weakly prime, because it can be changed into another prime (142033213423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71016606716 + 71016606717.

It is an arithmetic number, because the mean of its divisors is an integer number (71016606717).

Almost surely, 2142033213433 is an apocalyptic number.

It is an amenable number.

142033213433 is a deficient number, since it is larger than the sum of its proper divisors (1).

142033213433 is an equidigital number, since it uses as much as digits as its factorization.

142033213433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 142033213433 its reverse (334312330241), we get a palindrome (476345543674).

The spelling of 142033213433 in words is "one hundred forty-two billion, thirty-three million, two hundred thirteen thousand, four hundred thirty-three".