14203325137 has 2 divisors, whose sum is σ = 14203325138. Its totient is φ = 14203325136.

The previous prime is 14203325093. The next prime is 14203325173. The reversal of 14203325137 is 73152330241.

14203325137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (14203325173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13708663056 + 494662081 = 117084^2 + 22241^2 .

It is a cyclic number.

It is not a de Polignac number, because 14203325137 - 2⁷ = 14203325009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14203325099 and 14203325108.

It is not a weakly prime, because it can be changed into another prime (14203325177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101662568 + 7101662569.

It is an arithmetic number, because the mean of its divisors is an integer number (7101662569).

Almost surely, 2^14203325137 is an apocalyptic number.

It is an amenable number.

14203325137 is a deficient number, since it is larger than the sum of its proper divisors (1).

14203325137 is an equidigital number, since it uses as much as digits as its factorization.

14203325137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 14203325137 its reverse (73152330241), we get a palindrome (87355655378).

The spelling of 14203325137 in words is "fourteen billion, two hundred three million, three hundred twenty-five thousand, one hundred thirty-seven".