Base | Representation |
---|---|
bin | 1100111010110000010110… |
… | …1000010111000010110111 |
3 | 1212021211211220122002100220 |
4 | 3032230011220113002313 |
5 | 3330202333114022403 |
6 | 50113004342105423 |
7 | 2664113146104024 |
oct | 316540550270267 |
9 | 55254756562326 |
10 | 14203551314103 |
11 | 4586768481718 |
12 | 17148b071b273 |
13 | 7c0509c37cc8 |
14 | 37165406854b |
15 | 199701018953 |
hex | ceb05a170b7 |
14203551314103 has 16 divisors (see below), whose sum is σ = 19341138754560. Its totient is φ = 9267501806496.
The previous prime is 14203551314063. The next prime is 14203551314189. The reversal of 14203551314103 is 30141315530241.
14203551314103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14203551314103 - 29 = 14203551313591 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14203551324103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29204838 + ... + 29687196.
It is an arithmetic number, because the mean of its divisors is an integer number (1208821172160).
Almost surely, 214203551314103 is an apocalyptic number.
14203551314103 is a deficient number, since it is larger than the sum of its proper divisors (5137587440457).
14203551314103 is a wasteful number, since it uses less digits than its factorization.
14203551314103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 691246.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 14203551314103 its reverse (30141315530241), we get a palindrome (44344866844344).
The spelling of 14203551314103 in words is "fourteen trillion, two hundred three billion, five hundred fifty-one million, three hundred fourteen thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •