Base | Representation |
---|---|
bin | 1100111010110010011001… |
… | …0110100111100100101101 |
3 | 1212021220021011200000222221 |
4 | 3032230212112213210231 |
5 | 3330204444134430331 |
6 | 50113135033035341 |
7 | 2664132563361043 |
oct | 316544626474455 |
9 | 55256234600887 |
10 | 14204100311341 |
11 | 4586a1a364446 |
12 | 1714a24555b51 |
13 | 7c05968b6c45 |
14 | 3716a6d36393 |
15 | 19973430e711 |
hex | ceb265a792d |
14204100311341 has 4 divisors (see below), whose sum is σ = 14204182737472. Its totient is φ = 14204017885212.
The previous prime is 14204100311299. The next prime is 14204100311371. The reversal of 14204100311341 is 14311300140241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14204100311341 - 211 = 14204100309293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14204100311371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40954035 + ... + 41299408.
It is an arithmetic number, because the mean of its divisors is an integer number (3551045684368).
Almost surely, 214204100311341 is an apocalyptic number.
It is an amenable number.
14204100311341 is a deficient number, since it is larger than the sum of its proper divisors (82426131).
14204100311341 is an equidigital number, since it uses as much as digits as its factorization.
14204100311341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82426130.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14204100311341 its reverse (14311300140241), we get a palindrome (28515400451582).
The spelling of 14204100311341 in words is "fourteen trillion, two hundred four billion, one hundred million, three hundred eleven thousand, three hundred forty-one".
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