142043113233311 has 4 divisors (see below), whose sum is σ = 149519066561400. Its totient is φ = 134567159905224.

The previous prime is 142043113233299. The next prime is 142043113233317. The reversal of 142043113233311 is 113332311340241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142043113233311 is a prime.

It is a super-2 number, since 2×142043113233311² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142043113233317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3737976664016 + ... + 3737976664053.

It is an arithmetic number, because the mean of its divisors is an integer number (37379766640350).

Almost surely, 2^{142043113233311} is an apocalyptic number.

142043113233311 is a deficient number, since it is larger than the sum of its proper divisors (7475953328089).

142043113233311 is an equidigital number, since it uses as much as digits as its factorization.

142043113233311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7475953328088.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 142043113233311 its reverse (113332311340241), we get a palindrome (255375424573552).

The spelling of 142043113233311 in words is "one hundred forty-two trillion, forty-three billion, one hundred thirteen million, two hundred thirty-three thousand, three hundred eleven".