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14204311409993 is a prime number
BaseRepresentation
bin1100111010110011001011…
…1011111001010101001001
31212021220210212212221220112
43032230302323321111021
53330210412210104433
650113212013404105
72664141035602025
oct316546273712511
955256725787815
1014204311409993
114587018537a41
121714a83199635
137c05cb558ba3
143716c6da7385
15199747b0c348
hexceb32ef9549

14204311409993 has 2 divisors, whose sum is σ = 14204311409994. Its totient is φ = 14204311409992.

The previous prime is 14204311409989. The next prime is 14204311410019. The reversal of 14204311409993 is 39990411340241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12815562293689 + 1388749116304 = 3579883^2 + 1178452^2 .

It is an emirp because it is prime and its reverse (39990411340241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14204311409993 - 22 = 14204311409989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14204311409923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102155704996 + 7102155704997.

It is an arithmetic number, because the mean of its divisors is an integer number (7102155704997).

Almost surely, 214204311409993 is an apocalyptic number.

It is an amenable number.

14204311409993 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204311409993 is an equidigital number, since it uses as much as digits as its factorization.

14204311409993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 50.

The spelling of 14204311409993 in words is "fourteen trillion, two hundred four billion, three hundred eleven million, four hundred nine thousand, nine hundred ninety-three".