Base | Representation |
---|---|
bin | 1100111010110011100110… |
… | …0011110100111110010001 |
3 | 1212021221002122000000021012 |
4 | 3032230321203310332101 |
5 | 3330211124132304301 |
6 | 50113231023340305 |
7 | 2664143555314514 |
oct | 316547143647621 |
9 | 55257078000235 |
10 | 14204422541201 |
11 | 4587075241512 |
12 | 1714ab4451695 |
13 | 7c06185990b9 |
14 | 3716d7a54d7b |
15 | 19975275eebb |
hex | ceb398f4f91 |
14204422541201 has 4 divisors (see below), whose sum is σ = 14952023727600. Its totient is φ = 13456821354804.
The previous prime is 14204422541191. The next prime is 14204422541249. The reversal of 14204422541201 is 10214522440241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 14204422541201 - 26 = 14204422541137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14204422541251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373800593171 + ... + 373800593208.
It is an arithmetic number, because the mean of its divisors is an integer number (3738005931900).
Almost surely, 214204422541201 is an apocalyptic number.
It is an amenable number.
14204422541201 is a deficient number, since it is larger than the sum of its proper divisors (747601186399).
14204422541201 is an equidigital number, since it uses as much as digits as its factorization.
14204422541201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 747601186398.
The product of its (nonzero) digits is 20480, while the sum is 32.
Adding to 14204422541201 its reverse (10214522440241), we get a palindrome (24418944981442).
The spelling of 14204422541201 in words is "fourteen trillion, two hundred four billion, four hundred twenty-two million, five hundred forty-one thousand, two hundred one".
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