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14204422541251 is a prime number
BaseRepresentation
bin1100111010110011100110…
…0011110100111111000011
31212021221002122000000100001
43032230321203310333003
53330211124132310001
650113231023340431
72664143555314615
oct316547143647703
955257078000301
1014204422541251
114587075241558
121714ab4451717
137c0618599127
143716d7a54db5
15199752760001
hexceb398f4fc3

14204422541251 has 2 divisors, whose sum is σ = 14204422541252. Its totient is φ = 14204422541250.

The previous prime is 14204422541249. The next prime is 14204422541269. The reversal of 14204422541251 is 15214522440241.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14204422541251 - 21 = 14204422541249 is a prime.

Together with 14204422541249, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 14204422541251.

It is not a weakly prime, because it can be changed into another prime (14204422541851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102211270625 + 7102211270626.

It is an arithmetic number, because the mean of its divisors is an integer number (7102211270626).

Almost surely, 214204422541251 is an apocalyptic number.

14204422541251 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204422541251 is an equidigital number, since it uses as much as digits as its factorization.

14204422541251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 102400, while the sum is 37.

Adding to 14204422541251 its reverse (15214522440241), we get a palindrome (29418944981492).

It can be divided in two parts, 1420442 and 2541251, that added together give a palindrome (3961693).

The spelling of 14204422541251 in words is "fourteen trillion, two hundred four billion, four hundred twenty-two million, five hundred forty-one thousand, two hundred fifty-one".