Base | Representation |
---|---|
bin | 1100111010110110111101… |
… | …0011100110001101100111 |
3 | 1212022000102110201212120102 |
4 | 3032231233103212031213 |
5 | 3330220001002143403 |
6 | 50113500314254315 |
7 | 2664205114625111 |
oct | 316555723461547 |
9 | 55260373655512 |
10 | 14205324256103 |
11 | 4587498235242 |
12 | 171510642739b |
13 | 7c0730343206 |
14 | 3717816da3b1 |
15 | 1997a69c9b88 |
hex | ceb6f4e6367 |
14205324256103 has 4 divisors (see below), whose sum is σ = 14205466809360. Its totient is φ = 14205181702848.
The previous prime is 14205324256073. The next prime is 14205324256127. The reversal of 14205324256103 is 30165242350241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14205324256103 - 216 = 14205324190567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14205324256183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71127050 + ... + 71326487.
It is an arithmetic number, because the mean of its divisors is an integer number (3551366702340).
Almost surely, 214205324256103 is an apocalyptic number.
14205324256103 is a deficient number, since it is larger than the sum of its proper divisors (142553257).
14205324256103 is an equidigital number, since it uses as much as digits as its factorization.
14205324256103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142553256.
The product of its (nonzero) digits is 172800, while the sum is 38.
The spelling of 14205324256103 in words is "fourteen trillion, two hundred five billion, three hundred twenty-four million, two hundred fifty-six thousand, one hundred three".
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