Base | Representation |
---|---|
bin | 1100111011001000100101… |
… | …0011010000010011111111 |
3 | 1212022110122012002220101111 |
4 | 3032302021103100103333 |
5 | 3330304143131410221 |
6 | 50120002002022451 |
7 | 2664433263321334 |
oct | 316621123202377 |
9 | 55273565086344 |
10 | 14210055341311 |
11 | 45894a586a615 |
12 | 1716006947a27 |
13 | 7c1005568c0b |
14 | 371aadb9a98b |
15 | 199982012be1 |
hex | cec894d04ff |
14210055341311 has 4 divisors (see below), whose sum is σ = 14210908866000. Its totient is φ = 14209201816624.
The previous prime is 14210055341303. The next prime is 14210055341357. The reversal of 14210055341311 is 11314355001241.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14210055341311 - 23 = 14210055341303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14210055341371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426737371 + ... + 426770668.
It is an arithmetic number, because the mean of its divisors is an integer number (3552727216500).
Almost surely, 214210055341311 is an apocalyptic number.
14210055341311 is a deficient number, since it is larger than the sum of its proper divisors (853524689).
14210055341311 is an equidigital number, since it uses as much as digits as its factorization.
14210055341311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 853524688.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 14210055341311 in words is "fourteen trillion, two hundred ten billion, fifty-five million, three hundred forty-one thousand, three hundred eleven".
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