Base | Representation |
---|---|
bin | 10100101011011111000… |
… | …000001011010100111011 |
3 | 12000212001112210212112211 |
4 | 110223133000023110323 |
5 | 141240333111320433 |
6 | 3004500240315551 |
7 | 204445462366162 |
oct | 24533700132473 |
9 | 5025045725484 |
10 | 1421080573243 |
11 | 4a8749a32a51 |
12 | 1ab4b9012bb7 |
13 | a401311cc56 |
14 | 4cad02143d9 |
15 | 26e73bc58cd |
hex | 14adf00b53b |
1421080573243 has 2 divisors, whose sum is σ = 1421080573244. Its totient is φ = 1421080573242.
The previous prime is 1421080573153. The next prime is 1421080573259. The reversal of 1421080573243 is 3423750801241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1421080573243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1421080573196 and 1421080573205.
It is not a weakly prime, because it can be changed into another prime (1421081573243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710540286621 + 710540286622.
It is an arithmetic number, because the mean of its divisors is an integer number (710540286622).
Almost surely, 21421080573243 is an apocalyptic number.
1421080573243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421080573243 is an equidigital number, since it uses as much as digits as its factorization.
1421080573243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 40.
The spelling of 1421080573243 in words is "one trillion, four hundred twenty-one billion, eighty million, five hundred seventy-three thousand, two hundred forty-three".
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