Base | Representation |
---|---|
bin | 100000010011111110010000… |
… | …101111001111000001000110 |
3 | 200122011120210000121121120000 |
4 | 200103332100233033001012 |
5 | 122111312300333133014 |
6 | 1222124234330222130 |
7 | 41635052361543042 |
oct | 4023762057170106 |
9 | 618146700547500 |
10 | 142110011224134 |
11 | 4130a576598a88 |
12 | 13b31a57284946 |
13 | 613abbb8a1765 |
14 | 2714238643022 |
15 | 116691a57c509 |
hex | 813f90bcf046 |
142110011224134 has 80 divisors (see below), whose sum is σ = 319532421083568. Its totient is φ = 47206320257088.
The previous prime is 142110011224073. The next prime is 142110011224157. The reversal of 142110011224134 is 431422110011241.
142110011224134 is a `hidden beast` number, since 1 + 4 + 21 + 100 + 1 + 122 + 413 + 4 = 666.
It is a super-2 number, since 2×1421100112241342 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 142110011224098 and 142110011224107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 252218112 + ... + 252780924.
Almost surely, 2142110011224134 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 142110011224134, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159766210541784).
142110011224134 is an abundant number, since it is smaller than the sum of its proper divisors (177422409859434).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142110011224134 is a wasteful number, since it uses less digits than its factorization.
142110011224134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 568211 (or 568202 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 27.
Adding to 142110011224134 its reverse (431422110011241), we get a palindrome (573532121235375).
The spelling of 142110011224134 in words is "one hundred forty-two trillion, one hundred ten billion, eleven million, two hundred twenty-four thousand, one hundred thirty-four".
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