14211030032421 has 4 divisors (see below), whose sum is σ = 18948040043232. Its totient is φ = 9474020021612.

The previous prime is 14211030032401. The next prime is 14211030032443. The reversal of 14211030032421 is 12423003011241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14211030032421 - 2⁶ = 14211030032357 is a prime.

It is a super-2 number, since 2×14211030032421² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14211030032391 and 14211030032400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14211030032401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368505005401 + ... + 2368505005406.

It is an arithmetic number, because the mean of its divisors is an integer number (4737010010808).

Almost surely, 2^{14211030032421} is an apocalyptic number.

It is an amenable number.

14211030032421 is a deficient number, since it is larger than the sum of its proper divisors (4737010010811).

14211030032421 is an equidigital number, since it uses as much as digits as its factorization.

14211030032421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4737010010810.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 14211030032421 its reverse (12423003011241), we get a palindrome (26634033043662).

The spelling of 14211030032421 in words is "fourteen trillion, two hundred eleven billion, thirty million, thirty-two thousand, four hundred twenty-one".