Base | Representation |
---|---|
bin | 1100111011001100111001… |
… | …0101000100000101001010 |
3 | 1212022120121220021120210112 |
4 | 3032303032111010011022 |
5 | 3330314031120142102 |
6 | 50120312532114322 |
7 | 2664504055115303 |
oct | 316631625040512 |
9 | 55276556246715 |
10 | 14211213443402 |
11 | 4589a3a559888 |
12 | 171628a7659a2 |
13 | 7c115b480a21 |
14 | 371b7d9017aa |
15 | 1999eda24252 |
hex | cecce54414a |
14211213443402 has 8 divisors (see below), whose sum is σ = 21318172202016. Its totient is φ = 7105156042732.
The previous prime is 14211213443389. The next prime is 14211213443411. The reversal of 14211213443402 is 20434431211241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225300068 + ... + 225363135.
It is an arithmetic number, because the mean of its divisors is an integer number (2664771525252).
Almost surely, 214211213443402 is an apocalyptic number.
14211213443402 is a deficient number, since it is larger than the sum of its proper divisors (7106958758614).
14211213443402 is a wasteful number, since it uses less digits than its factorization.
14211213443402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 450678972.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 14211213443402 its reverse (20434431211241), we get a palindrome (34645644654643).
The spelling of 14211213443402 in words is "fourteen trillion, two hundred eleven billion, two hundred thirteen million, four hundred forty-three thousand, four hundred two".
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