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14211242133 = 3111061340577
BaseRepresentation
bin11010011110000111…
…00101100010010101
31100200101221220022020
431033003211202111
5213101034222013
610310100123353
71012111364544
oct151703454225
940611856266
1014211242133
11603296a610
122907396559
13145630121a
1498b58415b
1558295d623
hex34f0e5895

14211242133 has 16 divisors (see below), whose sum is σ = 20673354816. Its totient is φ = 8611850240.

The previous prime is 14211242131. The next prime is 14211242159. The reversal of 14211242133 is 33124211241.

14211242133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 14211242133 - 21 = 14211242131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14211242131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 329941 + ... + 370517.

It is an arithmetic number, because the mean of its divisors is an integer number (1292084676).

Almost surely, 214211242133 is an apocalyptic number.

It is an amenable number.

14211242133 is a deficient number, since it is larger than the sum of its proper divisors (6462112683).

14211242133 is a wasteful number, since it uses less digits than its factorization.

14211242133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51204.

The product of its digits is 1152, while the sum is 24.

Adding to 14211242133 its reverse (33124211241), we get a palindrome (47335453374).

The spelling of 14211242133 in words is "fourteen billion, two hundred eleven million, two hundred forty-two thousand, one hundred thirty-three".

Divisors: 1 3 11 33 10613 31839 40577 116743 121731 350229 446347 1339041 430643701 1291931103 4737080711 14211242133