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142115331040000 = 285422310493797
BaseRepresentation
bin100000010100000011001101…
…110100101110001100000000
3200122012002111202210021000021
4200110003031310232030000
5122111404144221240000
61222130514244303224
741635331246331223
oct4024031564561400
9618162452707007
10142115331040000
114131185648441a
1213b32aa09a1b14
13613b558a787b6
1427145c0d955ba
151166b2c60911a
hex8140cdd2e300

142115331040000 has 360 divisors, whose sum is σ = 356503839753600. Its totient is φ = 56522379264000.

The previous prime is 142115331039971. The next prime is 142115331040003. The reversal of 142115331040000 is 40133511241.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (142115331040003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 37428318102 + ... + 37428321898.

It is an arithmetic number, because the mean of its divisors is an integer number (990288443760).

Almost surely, 2142115331040000 is an apocalyptic number.

142115331040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 142115331040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178251919876800).

142115331040000 is an abundant number, since it is smaller than the sum of its proper divisors (214388508713600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

142115331040000 is an equidigital number, since it uses as much as digits as its factorization.

142115331040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5105 (or 5076 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 142115331040000 its reverse (40133511241), we get a palindrome (142155464551241).

The spelling of 142115331040000 in words is "one hundred forty-two trillion, one hundred fifteen billion, three hundred thirty-one million, forty thousand".