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142120122140153 is a prime number
BaseRepresentation
bin100000010100000111101011…
…011001010100010111111001
3200122012112212200002100212002
4200110013223121110113321
5122111444002231441103
61222133025514230345
741635561054113233
oct4024075331242771
9618175780070762
10142120122140153
114131389497a923
1213b339b94253b5
13613bb405551c1
1427149173d9253
151166d0d049488
hex8141eb6545f9

142120122140153 has 2 divisors, whose sum is σ = 142120122140154. Its totient is φ = 142120122140152.

The previous prime is 142120122140111. The next prime is 142120122140197. The reversal of 142120122140153 is 351041221021241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71692578319609 + 70427543820544 = 8467147^2 + 8392112^2 .

It is a cyclic number.

It is not a de Polignac number, because 142120122140153 - 26 = 142120122140089 is a prime.

It is not a weakly prime, because it can be changed into another prime (142120122140653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71060061070076 + 71060061070077.

It is an arithmetic number, because the mean of its divisors is an integer number (71060061070077).

Almost surely, 2142120122140153 is an apocalyptic number.

It is an amenable number.

142120122140153 is a deficient number, since it is larger than the sum of its proper divisors (1).

142120122140153 is an equidigital number, since it uses as much as digits as its factorization.

142120122140153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 142120122140153 its reverse (351041221021241), we get a palindrome (493161343161394).

The spelling of 142120122140153 in words is "one hundred forty-two trillion, one hundred twenty billion, one hundred twenty-two million, one hundred forty thousand, one hundred fifty-three".