142120134433421 has 4 divisors (see below), whose sum is σ = 142485481823100. Its totient is φ = 141754787043744.

The previous prime is 142120134433411. The next prime is 142120134433423. The reversal of 142120134433421 is 124334431021241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 30568303957321 + 111551830476100 = 5528861^2 + 10561810^2 .

It is a cyclic number.

It is not a de Polignac number, because 142120134433421 - 2¹⁸ = 142120134171277 is a prime.

It is a super-2 number, since 2×142120134433421² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142120134433423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182673694256 + ... + 182673695033.

It is an arithmetic number, because the mean of its divisors is an integer number (35621370455775).

Almost surely, 2^{142120134433421} is an apocalyptic number.

It is an amenable number.

142120134433421 is a deficient number, since it is larger than the sum of its proper divisors (365347389679).

142120134433421 is an equidigital number, since it uses as much as digits as its factorization.

142120134433421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 365347389678.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 142120134433421 its reverse (124334431021241), we get a palindrome (266454565454662).

The spelling of 142120134433421 in words is "one hundred forty-two trillion, one hundred twenty billion, one hundred thirty-four million, four hundred thirty-three thousand, four hundred twenty-one".