14212113320 has 16 divisors (see below), whose sum is σ = 31977255060. Its totient is φ = 5684845312.

The previous prime is 14212113319. The next prime is 14212113337. The reversal of 14212113320 is 2331121241.

It can be written as a sum of positive squares in 2 ways, for example, as 13127201476 + 1084911844 = 114574^2 + 32938^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 14212113292 and 14212113301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177651377 + ... + 177651456.

Almost surely, 2^14212113320 is an apocalyptic number.

14212113320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14212113320 is an abundant number, since it is smaller than the sum of its proper divisors (17765141740).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14212113320 is a wasteful number, since it uses less digits than its factorization.

14212113320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 355302844 (or 355302840 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14212113320 its reverse (2331121241), we get a palindrome (16543234561).

The spelling of 14212113320 in words is "fourteen billion, two hundred twelve million, one hundred thirteen thousand, three hundred twenty".