14212124014537 has 2 divisors, whose sum is σ = 14212124014538. Its totient is φ = 14212124014536.

The previous prime is 14212124014493. The next prime is 14212124014579. The reversal of 14212124014537 is 73541042121241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13795422779961 + 416701234576 = 3714219^2 + 645524^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14212124014537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14212124014496 and 14212124014505.

It is not a weakly prime, because it can be changed into another prime (14212124014937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106062007268 + 7106062007269.

It is an arithmetic number, because the mean of its divisors is an integer number (7106062007269).

Almost surely, 2^{14212124014537} is an apocalyptic number.

It is an amenable number.

14212124014537 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212124014537 is an equidigital number, since it uses as much as digits as its factorization.

14212124014537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 53760, while the sum is 37.

Adding to 14212124014537 its reverse (73541042121241), we get a palindrome (87753166135778).

The spelling of 14212124014537 in words is "fourteen trillion, two hundred twelve billion, one hundred twenty-four million, fourteen thousand, five hundred thirty-seven".