Base | Representation |
---|---|
bin | 10100101011101000100… |
… | …001100100100111110111 |
3 | 12000212110200101222101212 |
4 | 110223220201210213313 |
5 | 141241200010310201 |
6 | 3004524144312035 |
7 | 204452442262460 |
oct | 24535041444767 |
9 | 5025420358355 |
10 | 1421240322551 |
11 | 4a8821123a75 |
12 | 1ab54261261b |
13 | a403a25357a |
14 | 4cb07519d67 |
15 | 26e82c2dabb |
hex | 14ae88649f7 |
1421240322551 has 16 divisors (see below), whose sum is σ = 1663949806848. Its totient is φ = 1188451723200.
The previous prime is 1421240322517. The next prime is 1421240322577. The reversal of 1421240322551 is 1552230421241.
It is a de Polignac number, because none of the positive numbers 2k-1421240322551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1421240322581) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10148516 + ... + 10287606.
It is an arithmetic number, because the mean of its divisors is an integer number (103996862928).
Almost surely, 21421240322551 is an apocalyptic number.
1421240322551 is a deficient number, since it is larger than the sum of its proper divisors (242709484297).
1421240322551 is a wasteful number, since it uses less digits than its factorization.
1421240322551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 174742.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 1421240322551 its reverse (1552230421241), we get a palindrome (2973470743792).
The spelling of 1421240322551 in words is "one trillion, four hundred twenty-one billion, two hundred forty million, three hundred twenty-two thousand, five hundred fifty-one".
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