Base | Representation |
---|---|
bin | 10100101011101000100… |
… | …100100111010111111011 |
3 | 12000212110201220111122022 |
4 | 110223220210213113323 |
5 | 141241200211322001 |
6 | 3004524213345055 |
7 | 204452452124231 |
oct | 24535044472773 |
9 | 5025421814568 |
10 | 1421241120251 |
11 | 4a8821619327 |
12 | 1ab54293818b |
13 | a403a472694 |
14 | 4cb07686951 |
15 | 26e82d3a11b |
hex | 14ae89275fb |
1421241120251 has 2 divisors, whose sum is σ = 1421241120252. Its totient is φ = 1421241120250.
The previous prime is 1421241120241. The next prime is 1421241120259. The reversal of 1421241120251 is 1520211421241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1421241120251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1421241120251.
It is not a weakly prime, because it can be changed into another prime (1421241120259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710620560125 + 710620560126.
It is an arithmetic number, because the mean of its divisors is an integer number (710620560126).
Almost surely, 21421241120251 is an apocalyptic number.
1421241120251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421241120251 is an equidigital number, since it uses as much as digits as its factorization.
1421241120251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1280, while the sum is 26.
Adding to 1421241120251 its reverse (1520211421241), we get a palindrome (2941452541492).
The spelling of 1421241120251 in words is "one trillion, four hundred twenty-one billion, two hundred forty-one million, one hundred twenty thousand, two hundred fifty-one".
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