142124303000043 has 48 divisors (see below), whose sum is σ = 263650880962560. Its totient is φ = 71707245077952.

The previous prime is 142124302999993. The next prime is 142124303000051. The reversal of 142124303000043 is 340000303421241.

142124303000043 is a `hidden beast` number, since 14 + 212 + 430 + 3 + 0 + 0 + 0 + 0 + 4 + 3 = 666.

It is not a de Polignac number, because 142124303000043 - 2⁶ = 142124302999979 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142124302999980 and 142124303000016.

It is not an unprimeable number, because it can be changed into a prime (142124103000043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3772458283 + ... + 3772495956.

It is an arithmetic number, because the mean of its divisors is an integer number (5492726686720).

Almost surely, 2^{142124303000043} is an apocalyptic number.

142124303000043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

142124303000043 is a deficient number, since it is larger than the sum of its proper divisors (121526577962517).

142124303000043 is a wasteful number, since it uses less digits than its factorization.

142124303000043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7544954288 (or 7544954285 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 142124303000043 its reverse (340000303421241), we get a palindrome (482124606421284).

The spelling of 142124303000043 in words is "one hundred forty-two trillion, one hundred twenty-four billion, three hundred three million, forty-three", and thus it is an aban number.