Base | Representation |
---|---|
bin | 100000010100001011100100… |
… | …100110000010000111110011 |
3 | 200122012221200001010001102222 |
4 | 200110023210212002013303 |
5 | 122112031033032000201 |
6 | 1222135000424431255 |
7 | 41636066501616161 |
oct | 4024134446020763 |
9 | 618187601101388 |
10 | 142124303000051 |
11 | 4131563a963839 |
12 | 13b3478561852b |
13 | 613c35878bcb8 |
14 | 2714bd278c231 |
15 | 1166ea50e791b |
hex | 8142e49821f3 |
142124303000051 has 2 divisors, whose sum is σ = 142124303000052. Its totient is φ = 142124303000050.
The previous prime is 142124302999993. The next prime is 142124303000137. The reversal of 142124303000051 is 150000303421241.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142124303000051 is a prime.
It is not a weakly prime, because it can be changed into another prime (142124303000651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71062151500025 + 71062151500026.
It is an arithmetic number, because the mean of its divisors is an integer number (71062151500026).
Almost surely, 2142124303000051 is an apocalyptic number.
142124303000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
142124303000051 is an equidigital number, since it uses as much as digits as its factorization.
142124303000051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 142124303000051 its reverse (150000303421241), we get a palindrome (292124606421292).
The spelling of 142124303000051 in words is "one hundred forty-two trillion, one hundred twenty-four billion, three hundred three million, fifty-one", and thus it is an aban number.
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