Base | Representation |
---|---|
bin | 11010011110010000… |
… | …01001000101111011 |
3 | 1100200111012120110101 |
4 | 31033020021011323 |
5 | 213101340430342 |
6 | 10310141500231 |
7 | 1012124500324 |
oct | 151710110573 |
9 | 40614176411 |
10 | 14212436347 |
11 | 603360586a |
12 | 2907871677 |
13 | 145662b965 |
14 | 98b7b544b |
15 | 582ae73b7 |
hex | 34f20917b |
14212436347 has 2 divisors, whose sum is σ = 14212436348. Its totient is φ = 14212436346.
The previous prime is 14212436341. The next prime is 14212436351. The reversal of 14212436347 is 74363421241.
14212436347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (74363421241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14212436347 - 27 = 14212436219 is a prime.
It is not a weakly prime, because it can be changed into another prime (14212436341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106218173 + 7106218174.
It is an arithmetic number, because the mean of its divisors is an integer number (7106218174).
Almost surely, 214212436347 is an apocalyptic number.
14212436347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212436347 is an equidigital number, since it uses as much as digits as its factorization.
14212436347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 96768, while the sum is 37.
Adding to 14212436347 its reverse (74363421241), we get a palindrome (88575857588).
The spelling of 14212436347 in words is "fourteen billion, two hundred twelve million, four hundred thirty-six thousand, three hundred forty-seven".
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