Base | Representation |
---|---|
bin | 10100101011101000110… |
… | …000110101010110011011 |
3 | 12000212110221221020022001 |
4 | 110223220300311112123 |
5 | 141241202021320402 |
6 | 3004524410141431 |
7 | 204452521264321 |
oct | 24535060652633 |
9 | 5025427836261 |
10 | 1421244323227 |
11 | 4a8823406813 |
12 | 1ab543a21877 |
13 | a403b024531 |
14 | 4cb07c7bd11 |
15 | 26e8326e187 |
hex | 14ae8c3559b |
1421244323227 has 2 divisors, whose sum is σ = 1421244323228. Its totient is φ = 1421244323226.
The previous prime is 1421244323197. The next prime is 1421244323243. The reversal of 1421244323227 is 7223234421241.
It is a strong prime.
It is an emirp because it is prime and its reverse (7223234421241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1421244323227 - 231 = 1419096839579 is a prime.
It is not a weakly prime, because it can be changed into another prime (1421244323027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710622161613 + 710622161614.
It is an arithmetic number, because the mean of its divisors is an integer number (710622161614).
Almost surely, 21421244323227 is an apocalyptic number.
1421244323227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421244323227 is an equidigital number, since it uses as much as digits as its factorization.
1421244323227 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129024, while the sum is 37.
Adding to 1421244323227 its reverse (7223234421241), we get a palindrome (8644478744468).
It can be divided in two parts, 1421244 and 323227, that added together give a palindrome (1744471).
The spelling of 1421244323227 in words is "one trillion, four hundred twenty-one billion, two hundred forty-four million, three hundred twenty-three thousand, two hundred twenty-seven".
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