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142125400057 is a prime number
BaseRepresentation
bin1000010001011101010…
…1010111111111111001
3111120211222000101111211
42010113111113333321
54312033100300212
6145142544323121
713160666652634
oct2042725277771
9446758011454
10142125400057
11553030a0713
12236656134a1
1310530004174
146c43a0ac1b
153a6c6049a7
hex2117557ff9

142125400057 has 2 divisors, whose sum is σ = 142125400058. Its totient is φ = 142125400056.

The previous prime is 142125400049. The next prime is 142125400181. The reversal of 142125400057 is 750004521241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138893363856 + 3232036201 = 372684^2 + 56851^2 .

It is a cyclic number.

It is not a de Polignac number, because 142125400057 - 23 = 142125400049 is a prime.

It is not a weakly prime, because it can be changed into another prime (142125400457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71062700028 + 71062700029.

It is an arithmetic number, because the mean of its divisors is an integer number (71062700029).

Almost surely, 2142125400057 is an apocalyptic number.

It is an amenable number.

142125400057 is a deficient number, since it is larger than the sum of its proper divisors (1).

142125400057 is an equidigital number, since it uses as much as digits as its factorization.

142125400057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11200, while the sum is 31.

Adding to 142125400057 its reverse (750004521241), we get a palindrome (892129921298).

The spelling of 142125400057 in words is "one hundred forty-two billion, one hundred twenty-five million, four hundred thousand, fifty-seven".