14213110101 has 4 divisors (see below), whose sum is σ = 18950813472. Its totient is φ = 9475406732.

The previous prime is 14213110063. The next prime is 14213110123. The reversal of 14213110101 is 10101131241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10101131241 = 3 ⋅3367043747.

It is a cyclic number.

It is not a de Polignac number, because 14213110101 - 2¹¹ = 14213108053 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14213110601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2368851681 + ... + 2368851686.

It is an arithmetic number, because the mean of its divisors is an integer number (4737703368).

Almost surely, 2^14213110101 is an apocalyptic number.

It is an amenable number.

14213110101 is a deficient number, since it is larger than the sum of its proper divisors (4737703371).

14213110101 is an equidigital number, since it uses as much as digits as its factorization.

14213110101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4737703370.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 14213110101 its reverse (10101131241), we get a palindrome (24314241342).

The spelling of 14213110101 in words is "fourteen billion, two hundred thirteen million, one hundred ten thousand, one hundred one".