Base | Representation |
---|---|
bin | 1100111011010011111101… |
… | …1101001101011010101001 |
3 | 1212022202112011121222112221 |
4 | 3032310333131031122221 |
5 | 3330331423004413301 |
6 | 50121225132034041 |
7 | 2664602102402563 |
oct | 316647735153251 |
9 | 55282464558487 |
10 | 14213111404201 |
11 | 458a823941926 |
12 | 171671a302921 |
13 | 7c13a174c358 |
14 | 371cbd9d8333 |
15 | 199ab047cda1 |
hex | ced3f74d6a9 |
14213111404201 has 8 divisors (see below), whose sum is σ = 14597787746304. Its totient is φ = 13830245304480.
The previous prime is 14213111404199. The next prime is 14213111404207. The reversal of 14213111404201 is 10240411131241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14213111404201 - 21 = 14213111404199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14213111404207) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 452544681 + ... + 452576086.
It is an arithmetic number, because the mean of its divisors is an integer number (1824723468288).
Almost surely, 214213111404201 is an apocalyptic number.
It is an amenable number.
14213111404201 is a deficient number, since it is larger than the sum of its proper divisors (384676342103).
14213111404201 is an equidigital number, since it uses as much as digits as its factorization.
14213111404201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 905121191.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 14213111404201 its reverse (10240411131241), we get a palindrome (24453522535442).
The spelling of 14213111404201 in words is "fourteen trillion, two hundred thirteen billion, one hundred eleven million, four hundred four thousand, two hundred one".
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