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14213111404207 is a prime number
BaseRepresentation
bin1100111011010011111101…
…1101001101011010101111
31212022202112011121222120011
43032310333131031122233
53330331423004413312
650121225132034051
72664602102402602
oct316647735153257
955282464558504
1014213111404207
11458a823941931
12171671a302927
137c13a174c361
14371cbd9d8339
15199ab047cda7
hexced3f74d6af

14213111404207 has 2 divisors, whose sum is σ = 14213111404208. Its totient is φ = 14213111404206.

The previous prime is 14213111404199. The next prime is 14213111404237. The reversal of 14213111404207 is 70240411131241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14213111404207 - 23 = 14213111404199 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14213111404237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106555702103 + 7106555702104.

It is an arithmetic number, because the mean of its divisors is an integer number (7106555702104).

Almost surely, 214213111404207 is an apocalyptic number.

14213111404207 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213111404207 is an equidigital number, since it uses as much as digits as its factorization.

14213111404207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 31.

Adding to 14213111404207 its reverse (70240411131241), we get a palindrome (84453522535448).

The spelling of 14213111404207 in words is "fourteen trillion, two hundred thirteen billion, one hundred eleven million, four hundred four thousand, two hundred seven".