14213120123 has 2 divisors, whose sum is σ = 14213120124. Its totient is φ = 14213120122.

The previous prime is 14213120101. The next prime is 14213120137. The reversal of 14213120123 is 32102131241.

14213120123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14213120123 - 2¹⁴ = 14213103739 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14213120095 and 14213120104.

It is not a weakly prime, because it can be changed into another prime (14213120723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106560061 + 7106560062.

It is an arithmetic number, because the mean of its divisors is an integer number (7106560062).

Almost surely, 2^14213120123 is an apocalyptic number.

14213120123 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213120123 is an equidigital number, since it uses as much as digits as its factorization.

14213120123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14213120123 its reverse (32102131241), we get a palindrome (46315251364).

The spelling of 14213120123 in words is "fourteen billion, two hundred thirteen million, one hundred twenty thousand, one hundred twenty-three".