Base | Representation |
---|---|
bin | 1100111011010100000011… |
… | …0000111001100101000010 |
3 | 1212022202120200220120222121 |
4 | 3032311000300321211002 |
5 | 3330331444113434132 |
6 | 50121231234154454 |
7 | 2664602460025324 |
oct | 316650060714502 |
9 | 55282520816877 |
10 | 14213133343042 |
11 | 458a8352668a7 |
12 | 1716725722a2a |
13 | 7c13a616110a |
14 | 371cc28a9614 |
15 | 199ab2363497 |
hex | ced40c39942 |
14213133343042 has 8 divisors (see below), whose sum is σ = 21611750699916. Its totient is φ = 7009216443072.
The previous prime is 14213133343033. The next prime is 14213133343091. The reversal of 14213133343042 is 24034333131241.
It can be written as a sum of positive squares in 2 ways, for example, as 14188850042481 + 24283300561 = 3766809^2 + 155831^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 14213133342989 and 14213133343007.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48675114043 + ... + 48675114334.
Almost surely, 214213133343042 is an apocalyptic number.
14213133343042 is a deficient number, since it is larger than the sum of its proper divisors (7398617356874).
14213133343042 is an equidigital number, since it uses as much as digits as its factorization.
14213133343042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97350228452.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 14213133343042 its reverse (24034333131241), we get a palindrome (38247466474283).
The spelling of 14213133343042 in words is "fourteen trillion, two hundred thirteen billion, one hundred thirty-three million, three hundred forty-three thousand, forty-two".
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