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14213248207 = 46730435221
BaseRepresentation
bin11010011110010110…
…01111010011001111
31100200112201211010021
431033023033103033
5213102042420312
610310211123011
71012134421264
oct151713172317
940615654107
1014213248207
11603400a824
122907ba3467
131456854352
1498b94726b
15582c07c07
hex34f2cf4cf

14213248207 has 4 divisors (see below), whose sum is σ = 14243683896. Its totient is φ = 14182812520.

The previous prime is 14213248193. The next prime is 14213248213. The reversal of 14213248207 is 70284231241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70284231241 = 710040604463.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14213248207 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14213248297) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15217144 + ... + 15218077.

It is an arithmetic number, because the mean of its divisors is an integer number (3560920974).

Almost surely, 214213248207 is an apocalyptic number.

14213248207 is a deficient number, since it is larger than the sum of its proper divisors (30435689).

14213248207 is an equidigital number, since it uses as much as digits as its factorization.

14213248207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30435688.

The product of its (nonzero) digits is 21504, while the sum is 34.

Adding to 14213248207 its reverse (70284231241), we get a palindrome (84497479448).

The spelling of 14213248207 in words is "fourteen billion, two hundred thirteen million, two hundred forty-eight thousand, two hundred seven".

Divisors: 1 467 30435221 14213248207