Base | Representation |
---|---|
bin | 11010011110010111… |
… | …10100011010101001 |
3 | 1100200120000112122212 |
4 | 31033023310122221 |
5 | 213102112301413 |
6 | 10310214254505 |
7 | 1012135623434 |
oct | 151713643251 |
9 | 40616015585 |
10 | 14213400233 |
11 | 6034103a6a |
12 | 2908057435 |
13 | 14568a85c6 |
14 | 98b98681b |
15 | 582c37ca8 |
hex | 34f2f46a9 |
14213400233 has 2 divisors, whose sum is σ = 14213400234. Its totient is φ = 14213400232.
The previous prime is 14213400217. The next prime is 14213400247. The reversal of 14213400233 is 33200431241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14135307664 + 78092569 = 118892^2 + 8837^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213400233 - 24 = 14213400217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14213400199 and 14213400208.
It is not a weakly prime, because it can be changed into another prime (14213400263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106700116 + 7106700117.
It is an arithmetic number, because the mean of its divisors is an integer number (7106700117).
Almost surely, 214213400233 is an apocalyptic number.
It is an amenable number.
14213400233 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213400233 is an equidigital number, since it uses as much as digits as its factorization.
14213400233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 14213400233 its reverse (33200431241), we get a palindrome (47413831474).
The spelling of 14213400233 in words is "fourteen billion, two hundred thirteen million, four hundred thousand, two hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •