14213410400113 has 8 divisors (see below), whose sum is σ = 14270827207680. Its totient is φ = 14156042070240.

The previous prime is 14213410400099. The next prime is 14213410400117. The reversal of 14213410400113 is 31100401431241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14213410400113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14213410400117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11531793 + ... + 12704686.

It is an arithmetic number, because the mean of its divisors is an integer number (1783853400960).

Almost surely, 2^{14213410400113} is an apocalyptic number.

It is an amenable number.

14213410400113 is a deficient number, since it is larger than the sum of its proper divisors (57416807567).

14213410400113 is a wasteful number, since it uses less digits than its factorization.

14213410400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24238847.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14213410400113 its reverse (31100401431241), we get a palindrome (45313811831354).

The spelling of 14213410400113 in words is "fourteen trillion, two hundred thirteen billion, four hundred ten million, four hundred thousand, one hundred thirteen".