Base | Representation |
---|---|
bin | 1000010001011111011… |
… | …0101011010111001001 |
3 | 111120212120102220220112 |
4 | 2010113312223113021 |
5 | 4312042314130441 |
6 | 145143455404105 |
7 | 13161134113004 |
oct | 2042766532711 |
9 | 446776386815 |
10 | 142134130121 |
11 | 55308013745 |
12 | 23668523635 |
13 | 10531a6c999 |
14 | 6c44c4053b |
15 | 3a6d27b4eb |
hex | 2117dab5c9 |
142134130121 has 2 divisors, whose sum is σ = 142134130122. Its totient is φ = 142134130120.
The previous prime is 142134130087. The next prime is 142134130139. The reversal of 142134130121 is 121031431241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 90261790096 + 51872340025 = 300436^2 + 227755^2 .
It is a cyclic number.
It is not a de Polignac number, because 142134130121 - 26 = 142134130057 is a prime.
It is a super-2 number, since 2×1421341301212 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142134130181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71067065060 + 71067065061.
It is an arithmetic number, because the mean of its divisors is an integer number (71067065061).
Almost surely, 2142134130121 is an apocalyptic number.
It is an amenable number.
142134130121 is a deficient number, since it is larger than the sum of its proper divisors (1).
142134130121 is an equidigital number, since it uses as much as digits as its factorization.
142134130121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 142134130121 its reverse (121031431241), we get a palindrome (263165561362).
The spelling of 142134130121 in words is "one hundred forty-two billion, one hundred thirty-four million, one hundred thirty thousand, one hundred twenty-one".
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