Base | Representation |
---|---|
bin | 1100111011010111010010… |
… | …0110110111111100011101 |
3 | 1212022211211022120100120121 |
4 | 3032311310212313330131 |
5 | 3330340234300131031 |
6 | 50121453424514541 |
7 | 2664633151060633 |
oct | 316656446677435 |
9 | 55284738510517 |
10 | 14214003130141 |
11 | 4590141232811 |
12 | 1716928a7ba51 |
13 | 7c14b4409939 |
14 | 371d661dd353 |
15 | 199b138c3011 |
hex | ced749b7f1d |
14214003130141 has 8 divisors (see below), whose sum is σ = 14332690199520. Its totient is φ = 14095786109328.
The previous prime is 14214003130121. The next prime is 14214003130153. The reversal of 14214003130141 is 14103130041241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14214003130141 - 25 = 14214003130109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14214003130121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117451411 + ... + 117572368.
It is an arithmetic number, because the mean of its divisors is an integer number (1791586274940).
Almost surely, 214214003130141 is an apocalyptic number.
It is an amenable number.
14214003130141 is a deficient number, since it is larger than the sum of its proper divisors (118687069379).
14214003130141 is a wasteful number, since it uses less digits than its factorization.
14214003130141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235024283.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14214003130141 its reverse (14103130041241), we get a palindrome (28317133171382).
The spelling of 14214003130141 in words is "fourteen trillion, two hundred fourteen billion, three million, one hundred thirty thousand, one hundred forty-one".
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