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142141220031 = 3375111263107
BaseRepresentation
bin1000010001100001000…
…1101110010010111111
3111120220001210010102210
42010120101232102333
54312101123020111
6145144311351503
713161251302206
oct2043021562277
9446801703383
10142141220031
1155311016478
122366a982593
1310533382ab5
146c45b6823d
153a6dbcc0a6
hex211846e4bf

142141220031 has 8 divisors (see below), whose sum is σ = 189526829184. Its totient is φ = 94758212120.

The previous prime is 142141220009. The next prime is 142141220041. The reversal of 142141220031 is 130022141241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 142141220031 - 210 = 142141219007 is a prime.

It is a super-2 number, since 2×1421412200312 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142141220041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 519021 + ... + 744086.

It is an arithmetic number, because the mean of its divisors is an integer number (23690853648).

Almost surely, 2142141220031 is an apocalyptic number.

142141220031 is a deficient number, since it is larger than the sum of its proper divisors (47385609153).

142141220031 is a wasteful number, since it uses less digits than its factorization.

142141220031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300621.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 142141220031 its reverse (130022141241), we get a palindrome (272163361272).

The spelling of 142141220031 in words is "one hundred forty-two billion, one hundred forty-one million, two hundred twenty thousand, thirty-one".

Divisors: 1 3 37511 112533 1263107 3789321 47380406677 142141220031