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14214123312113 is a prime number
BaseRepresentation
bin1100111011010111101111…
…0001010101001111110001
31212022212010200201020020202
43032311323301111033301
53330341011031441423
650121513400444545
72664636140440454
oct316657361251761
955285120636222
1014214123312113
1145901a305925a
121716961179755
137c150329862a
14371d7816549b
15199b1e212728
hexced7bc553f1

14214123312113 has 2 divisors, whose sum is σ = 14214123312114. Its totient is φ = 14214123312112.

The previous prime is 14214123312097. The next prime is 14214123312143. The reversal of 14214123312113 is 31121332141241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10186744622224 + 4027378689889 = 3191668^2 + 2006833^2 .

It is a cyclic number.

It is not a de Polignac number, because 14214123312113 - 24 = 14214123312097 is a prime.

It is not a weakly prime, because it can be changed into another prime (14214123312143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107061656056 + 7107061656057.

It is an arithmetic number, because the mean of its divisors is an integer number (7107061656057).

Almost surely, 214214123312113 is an apocalyptic number.

It is an amenable number.

14214123312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14214123312113 is an equidigital number, since it uses as much as digits as its factorization.

14214123312113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3456, while the sum is 29.

Adding to 14214123312113 its reverse (31121332141241), we get a palindrome (45335455453354).

The spelling of 14214123312113 in words is "fourteen trillion, two hundred fourteen billion, one hundred twenty-three million, three hundred twelve thousand, one hundred thirteen".