Base | Representation |
---|---|
bin | 1100111011010111101111… |
… | …0100000111001101010011 |
3 | 1212022212010202002021011011 |
4 | 3032311323310013031103 |
5 | 3330341011223303133 |
6 | 50121513424231351 |
7 | 2664636146564563 |
oct | 316657364071523 |
9 | 55285122067134 |
10 | 14214124041043 |
11 | 45901a3506983 |
12 | 171696146b557 |
13 | 7c1503492354 |
14 | 371d782b4da3 |
15 | 199b1e3086cd |
hex | ced7bd07353 |
14214124041043 has 2 divisors, whose sum is σ = 14214124041044. Its totient is φ = 14214124041042.
The previous prime is 14214124041023. The next prime is 14214124041049. The reversal of 14214124041043 is 34014042141241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14214124041043 - 229 = 14213587170131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14214124040996 and 14214124041014.
It is not a weakly prime, because it can be changed into another prime (14214124041049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107062020521 + 7107062020522.
It is an arithmetic number, because the mean of its divisors is an integer number (7107062020522).
Almost surely, 214214124041043 is an apocalyptic number.
14214124041043 is a deficient number, since it is larger than the sum of its proper divisors (1).
14214124041043 is an equidigital number, since it uses as much as digits as its factorization.
14214124041043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 14214124041043 its reverse (34014042141241), we get a palindrome (48228166182284).
The spelling of 14214124041043 in words is "fourteen trillion, two hundred fourteen billion, one hundred twenty-four million, forty-one thousand, forty-three".
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