Base | Representation |
---|---|
bin | 1100111011011000000100… |
… | …0111111000101010000010 |
3 | 1212022212100221200110100022 |
4 | 3032312001013320222002 |
5 | 3330341202024013102 |
6 | 50121530325253442 |
7 | 2664641310633164 |
oct | 316660107705202 |
9 | 55285327613308 |
10 | 14214213110402 |
11 | 4590239812018 |
12 | 1716987264282 |
13 | 7c1518a79806 |
14 | 371d8605c934 |
15 | 199b2704e5a2 |
hex | ced811f8a82 |
14214213110402 has 8 divisors (see below), whose sum is σ = 21682697965200. Its totient is φ = 6986647122004.
The previous prime is 14214213110359. The next prime is 14214213110423. The reversal of 14214213110402 is 20401131241241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60229716452 + ... + 60229716687.
It is an arithmetic number, because the mean of its divisors is an integer number (2710337245650).
Almost surely, 214214213110402 is an apocalyptic number.
14214213110402 is a deficient number, since it is larger than the sum of its proper divisors (7468484854798).
14214213110402 is a wasteful number, since it uses less digits than its factorization.
14214213110402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120459433200.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 14214213110402 its reverse (20401131241241), we get a palindrome (34615344351643).
The spelling of 14214213110402 in words is "fourteen trillion, two hundred fourteen billion, two hundred thirteen million, one hundred ten thousand, four hundred two".
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