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142144045533817 is a prime number
BaseRepresentation
bin100000010100011101111101…
…010101110100101001111001
3200122021211121221011200102021
4200110131331111310221321
5122112342001124040232
61222152023435434441
741640365646443515
oct4024357525645171
9618254557150367
10142144045533817
1141322a5101a648
1213b385752b5a21
136141183a0ba42
142715b467b3145
15116775d457397
hex81477d574a79

142144045533817 has 2 divisors, whose sum is σ = 142144045533818. Its totient is φ = 142144045533816.

The previous prime is 142144045533797. The next prime is 142144045533821. The reversal of 142144045533817 is 718335540441241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100582866868201 + 41561178665616 = 10029101^2 + 6446796^2 .

It is a cyclic number.

It is not a de Polignac number, because 142144045533817 - 27 = 142144045533689 is a prime.

It is a super-3 number, since 3×1421440455338173 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (142144045833817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71072022766908 + 71072022766909.

It is an arithmetic number, because the mean of its divisors is an integer number (71072022766909).

Almost surely, 2142144045533817 is an apocalyptic number.

It is an amenable number.

142144045533817 is a deficient number, since it is larger than the sum of its proper divisors (1).

142144045533817 is an equidigital number, since it uses as much as digits as its factorization.

142144045533817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6451200, while the sum is 52.

The spelling of 142144045533817 in words is "one hundred forty-two trillion, one hundred forty-four billion, forty-five million, five hundred thirty-three thousand, eight hundred seventeen".