Base | Representation |
---|---|
bin | 100000010101010010000110… |
… | …111100011101011010011111 |
3 | 200122111012011100221212202221 |
4 | 200111102012330131122133 |
5 | 122114301141023411111 |
6 | 1222233444101530211 |
7 | 41644420404150136 |
oct | 4025220674353237 |
9 | 618435140855687 |
10 | 142200041232031 |
11 | 41344776145492 |
12 | 13b473a2113967 |
13 | 614653899c493 |
14 | 271873951291d |
15 | 1168e39385371 |
hex | 815486f1d69f |
142200041232031 has 8 divisors (see below), whose sum is σ = 142509022777760. Its totient is φ = 141891129317088.
The previous prime is 142200041232019. The next prime is 142200041232047. The reversal of 142200041232031 is 130232140002241.
142200041232031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 142200041232031 - 217 = 142200041100959 is a prime.
It is a super-2 number, since 2×1422000412320312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 142200041231987 and 142200041232005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142200041232001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13317816 + ... + 21488701.
It is an arithmetic number, because the mean of its divisors is an integer number (17813627847220).
Almost surely, 2142200041232031 is an apocalyptic number.
142200041232031 is a deficient number, since it is larger than the sum of its proper divisors (308981545729).
142200041232031 is an equidigital number, since it uses as much as digits as its factorization.
142200041232031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34815393.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 142200041232031 its reverse (130232140002241), we get a palindrome (272432181234272).
The spelling of 142200041232031 in words is "one hundred forty-two trillion, two hundred billion, forty-one million, two hundred thirty-two thousand, thirty-one".
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