14220120120223 has 4 divisors (see below), whose sum is σ = 14220324030528. Its totient is φ = 14219916209920.

The previous prime is 14220120120137. The next prime is 14220120120257. The reversal of 14220120120223 is 32202102102241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14220120120223 - 2²¹ = 14220118023071 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14220120120194 and 14220120120203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14220120121223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101850511 + ... + 101990032.

It is an arithmetic number, because the mean of its divisors is an integer number (3555081007632).

Almost surely, 2^{14220120120223} is an apocalyptic number.

14220120120223 is a deficient number, since it is larger than the sum of its proper divisors (203910305).

14220120120223 is an equidigital number, since it uses as much as digits as its factorization.

14220120120223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203910304.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 14220120120223 its reverse (32202102102241), we get a palindrome (46422222222464).

The spelling of 14220120120223 in words is "fourteen trillion, two hundred twenty billion, one hundred twenty million, one hundred twenty thousand, two hundred twenty-three".