Search a number
-
+
14220120120224 = 25444378753757
BaseRepresentation
bin1100111011101110000100…
…1101010101101110100000
31212100102121121202122110212
43032323201031111232200
53330440301222321344
650124344421113252
72665240555453154
oct316734115255640
955312547678425
1014220120120224
1145927a00a9a17
121717b55558828
137c1c4a7b75b5
14372386783064
15199d7091979e
hexceee1355ba0

14220120120224 has 12 divisors (see below), whose sum is σ = 27995861486754. Its totient is φ = 7110060060096.

The previous prime is 14220120120137. The next prime is 14220120120257. The reversal of 14220120120224 is 42202102102241.

It can be written as a sum of positive squares in only one way, i.e., 13130042131600 + 1090077988624 = 3623540^2 + 1044068^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 14220120120224.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222189376847 + ... + 222189376910.

Almost surely, 214220120120224 is an apocalyptic number.

It is an amenable number.

14220120120224 is a deficient number, since it is larger than the sum of its proper divisors (13775741366530).

14220120120224 is an equidigital number, since it uses as much as digits as its factorization.

14220120120224 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444378753767 (or 444378753759 counting only the distinct ones).

The product of its (nonzero) digits is 1024, while the sum is 23.

Adding to 14220120120224 its reverse (42202102102241), we get a palindrome (56422222222465).

The spelling of 14220120120224 in words is "fourteen trillion, two hundred twenty billion, one hundred twenty million, one hundred twenty thousand, two hundred twenty-four".

Divisors: 1 2 4 8 16 32 444378753757 888757507514 1777515015028 3555030030056 7110060060112 14220120120224