Base | Representation |
---|---|
bin | 1000010001101111011… |
… | …0100100111000000111 |
3 | 111121001020200001112020 |
4 | 2010123312210320013 |
5 | 4312212002244143 |
6 | 145154253254223 |
7 | 13162610235144 |
oct | 2043366447007 |
9 | 447036601466 |
10 | 142201212423 |
11 | 55341971666 |
12 | 23686a94373 |
13 | 1054292945a |
14 | 6c4db033cb |
15 | 3a740cc883 |
hex | 211bda4e07 |
142201212423 has 4 divisors (see below), whose sum is σ = 189601616568. Its totient is φ = 94800808280.
The previous prime is 142201212409. The next prime is 142201212529. The reversal of 142201212423 is 324212102241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 142201212423 - 224 = 142184435207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142201212393 and 142201212402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142201211423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23700202068 + ... + 23700202073.
It is an arithmetic number, because the mean of its divisors is an integer number (47400404142).
Almost surely, 2142201212423 is an apocalyptic number.
142201212423 is a deficient number, since it is larger than the sum of its proper divisors (47400404145).
142201212423 is an equidigital number, since it uses as much as digits as its factorization.
142201212423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47400404144.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 142201212423 its reverse (324212102241), we get a palindrome (466413314664).
The spelling of 142201212423 in words is "one hundred forty-two billion, two hundred one million, two hundred twelve thousand, four hundred twenty-three".
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