Base | Representation |
---|---|
bin | 1000010001101111011… |
… | …1111000100001000011 |
3 | 111121001021022110110200 |
4 | 2010123313320201003 |
5 | 4312212044230021 |
6 | 145154304500243 |
7 | 13162613163015 |
oct | 2043367704103 |
9 | 447037273420 |
10 | 142201555011 |
11 | 55342085a9a |
12 | 2368701a683 |
13 | 10542a19379 |
14 | 6c4db921b5 |
15 | 3a74149126 |
hex | 211bdf8843 |
142201555011 has 24 divisors (see below), whose sum is σ = 219174730320. Its totient is φ = 88581206016.
The previous prime is 142201555003. The next prime is 142201555021. The reversal of 142201555011 is 110555102241.
It is a happy number.
142201555011 is a `hidden beast` number, since 1 + 4 + 2 + 2 + 0 + 155 + 501 + 1 = 666.
It is not a de Polignac number, because 142201555011 - 23 = 142201555003 is a prime.
It is a super-3 number, since 3×1422015550113 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (142201555021) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5683326 + ... + 5708291.
It is an arithmetic number, because the mean of its divisors is an integer number (9132280430).
Almost surely, 2142201555011 is an apocalyptic number.
142201555011 is a deficient number, since it is larger than the sum of its proper divisors (76973175309).
142201555011 is a wasteful number, since it uses less digits than its factorization.
142201555011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11391715 (or 11391712 counting only the distinct ones).
The product of its (nonzero) digits is 2000, while the sum is 27.
Adding to 142201555011 its reverse (110555102241), we get a palindrome (252756657252).
The spelling of 142201555011 in words is "one hundred forty-two billion, two hundred one million, five hundred fifty-five thousand, eleven".
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