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1422024112303 = 11931191973271
BaseRepresentation
bin10100101100010111001…
…111011111100010101111
312000221111022020121210221
4110230113033133202233
5141244301133043203
63005134023512211
7204511040343004
oct24542717374257
95027438217727
101422024112303
114a90935a28a3
121ab720bb8667
13a413374bca2
144cb7d6658ab
1526ecb952abd
hex14b173df8af

1422024112303 has 4 divisors (see below), whose sum is σ = 1423216086768. Its totient is φ = 1420832137840.

The previous prime is 1422024112297. The next prime is 1422024112307. The reversal of 1422024112303 is 3032114202241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1422024112303 - 233 = 1413434177711 is a prime.

It is a super-2 number, since 2×14220241123032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1422024112307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595985443 + ... + 595987828.

It is an arithmetic number, because the mean of its divisors is an integer number (355804021692).

Almost surely, 21422024112303 is an apocalyptic number.

1422024112303 is a deficient number, since it is larger than the sum of its proper divisors (1191974465).

1422024112303 is a wasteful number, since it uses less digits than its factorization.

1422024112303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1191974464.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1422024112303 its reverse (3032114202241), we get a palindrome (4454138314544).

The spelling of 1422024112303 in words is "one trillion, four hundred twenty-two billion, twenty-four million, one hundred twelve thousand, three hundred three".

Divisors: 1 1193 1191973271 1422024112303