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142233444332113 is a prime number
BaseRepresentation
bin100000010101110001001101…
…111011001011001001010001
3200122121101101021210011211211
4200111301031323023021101
5122120323043222111423
61222301050422140121
741650012225624441
oct4025611573131121
9618541337704754
10142233444332113
1141357957341a22
1213b51964881641
136149730104464
14271a1c78d4121
151169c41b2a10d
hex815c4decb251

142233444332113 has 2 divisors, whose sum is σ = 142233444332114. Its totient is φ = 142233444332112.

The previous prime is 142233444332047. The next prime is 142233444332117. The reversal of 142233444332113 is 311233444332241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97085688184849 + 45147756147264 = 9853207^2 + 6719208^2 .

It is an emirp because it is prime and its reverse (311233444332241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142233444332113 - 213 = 142233444323921 is a prime.

It is not a weakly prime, because it can be changed into another prime (142233444332117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71116722166056 + 71116722166057.

It is an arithmetic number, because the mean of its divisors is an integer number (71116722166057).

Almost surely, 2142233444332113 is an apocalyptic number.

It is an amenable number.

142233444332113 is a deficient number, since it is larger than the sum of its proper divisors (1).

142233444332113 is an equidigital number, since it uses as much as digits as its factorization.

142233444332113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 497664, while the sum is 40.

Adding to 142233444332113 its reverse (311233444332241), we get a palindrome (453466888664354).

The spelling of 142233444332113 in words is "one hundred forty-two trillion, two hundred thirty-three billion, four hundred forty-four million, three hundred thirty-two thousand, one hundred thirteen".